3(x^2+22x+112)=0

Solution for 3(x^2+22x+112)=0 equation:

3(x^2+22x+112)=0

We multiply parentheses

3x^2+66x+336=0

a = 3; b = 66; c = +336;
Δ = b2-4ac
Δ = 662-4·3·336
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-18}{2*3}=\frac{-84}{6}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+18}{2*3}=\frac{-48}{6}
=-8
$